Hello Phil,

On November 11, 2019 at 6:12 AM "Phil Pugliese (via tml list)" <xxxxxx@simplelists.com> wrote:

On 11 Nov2019 1309, Thomas RUX wrote:

> > > CT LBB 5 HG 2e 1980 TL 13 100-ton Express Boat: J4 Drive at 20 tons
> > > with 40 tons of fuel, Power Plant-4 at 12 tons with 2 tons of fuel,
> > > 20 ton bridge, 4 ton Model/4 computer, and one 2 ton small craft
> > > cabin without any cargo capacity.

On Monday, November 11, 2019, 03:45:23 AM MST, Rupert Boleyn <xxxxxx@gmail.com> wrote:
> > That jump drive seems far too big. A J-4 drive in HG should be 5% of the
> > ship's displacement, or 5 DTons. A TL-13 powerplant should be 2 x 4 = 8%
> > of the displacement, or 8 DTons.

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
> No matter which set of rules is used, IF the exception mentioned in, I believe, 'Traders &
> Gunboats' is allowed &, as a result, there is no PPlant nor MDrive, there should be plenty of
> space, shouldn't there?

In CT LBB 2 1977 I concluded that the Jump Drive was a specialized power plant that was not designed to run a ship's life support, computer, other electronic/electrical systems, maneuver drive, and weapons. Unfortunately, CT LBB 5 HG 5 added the requirement that the power plant number must be at least equal to the higher of the jump drive number or the maneuver drive number. MT Referee's Manual page 58 states that "jump drives are themselves a special high-yield power plant linked to an integral net in the craft's hull for initiating and maintaining the jump field."

If the jump drive's power plant is also supposed to take over the capabilities and duties of a standard power plant, per CT Supplement 7 page 9, to run life support, computer, and electronic/electrical systems then the cost, fuel requirements, and tonnage should probably go up too, but I'm not sure how much.

If I'm not out to lunch using CT LBB 2 1977 without a power plant and maneuver drive my calculations for the CT Supplement 7 X-boat is J4 Type-B drive at 15 tons with 40 tons of fuel, a 20 ton bridge, a 1 ton Model/1bis computer, two 4-ton staterooms, and 1 ton of cargo capacity which leave 11 tons. The X-boat has a maximum range of 4 on 40 tons of fuel and 3 days.

Since the CT LBB 2 power plant only has to be either the same type or a higher type than the maneuver drive I'm going to install a Power Plant-1 Type-A  which is 4 tons. The power plant Type-A requires 10 x 1 = 10 tons of fuel for 4 weeks. The combined total exceeds the 11 tons available. I'm going to reduce the 4 weeks of operation to 3 weeks which I think requires 10 x (3 / 4) = 10 x .75 = 7.5 tons of fuel, which is still over the 7 tons by 0.5 tons.  Cutting the time of operation to 2 weeks requires 10 x (2 / 4) = 10 x .25 = 2.5 tons of fuel. The combined total of a 4 ton Power Plant-1 Type-A  plus 2.5 tons of fuel for 2 weeks of operation is a total of 6.5 which leaves 4.5 tons available to add to the cargo capacity or maybe add another stateroom.

I don't think that the jump drive needs to add the full 4 tons of the power plant-1 type-A, but I do think it should be more than 15-tons, but the fuel requirement should be the same as for a power plant-1 type-A. The cost of the jump drive should also go up. Looking at the CT LBB 2 1977 Drives and Power Plants table on page 11 the change from a power plant type-A to type-B is 3 tons and the cost is MCr8.0. My thought would be to increase the J4 Type-B drive's mass by 3 tons and MCr8.0 since it is adding the functions and capacities of the power plant.

Tom Rux